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Good evening mam, Will you be having some online sessions for revision when the syllabus will be completed on your channel..?​@@Worldofchemistryclass11and12

@Jshndip45 Yes indeed

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Platinum (Pt) typically exhibits several common oxidation states, the most prevalent being +2 and +4. The hybridization and electron distribution of platinum can vary depending on its oxidation state and the type of ligands it is bonded to. Here’s a brief overview: Platinum in the +2 Oxidation State In the +2 oxidation state, platinum has a d8 electron configuration. A common complex for Pt(II) is square planar geometry. Example: [PtCl4]^{2-} **Electron configuration** The ground-state electron configuration for neutral Pt is [Xe] 4f14 5d9 6s1. - In the +2 oxidation state, it loses two electrons, resulting in [Xe] 4f14 5d8. Hybridization: The hybridization in the [PtCl4]^{2-} complex is dsp2. This involves the 5d, 6s, and two 6p orbitals hybridizing to form four hybrid orbitals. -Electron distribution: In the square planar geometry, the 5d8 configuration leads to electron pairing in the dx2-y2, dxy, dxz, and dyz orbitals, forming a stable configuration. Platinum in the +4 Oxidation State In the +4 oxidation state, platinum has a d6 electron configuration. A common geometry for Pt(IV) is octahedral. Example [PtCl6]^{2-} Electron configuration In the +4 oxidation state, platinum loses four electrons, resulting in [Xe] 4f14 5d6. Hybridization: The hybridization in the [PtCl6]^{2-} complex is d2sp3. This involves the 5d, 6s, and three 6p orbitals hybridizing to form six hybrid orbitals. Electron distribution: In an octahedral geometry, the 5d6 configuration allows for the pairing of electrons in the dx2-y2, dxy, dxz, dyz, and dz2 orbitals, forming stable bonds with six ligands. Summary Pt(II) Complex: Typically square planar with dsp2 hybridization. -Example: [PtCl4]^{2-} - Electron configuration: [Xe] 4f145d8 - Pt(IV) Complex: Typically octahedral with d2sp3 hybridization. Example: [PtCl6]^{2-} - Electron configuration: [Xe] 4f14 5d6 The specific hybridization and electron distribution can vary with different ligands and geometries, but these are common examples for Pt(II) and Pt(IV) complexes.

@@Worldofchemistryclass11and12 thank you so much ma'am

Welcome Ayan.. Happy learning

Zaroor

Yes. Log(3*5*100)= log3 + log5 + log100 =0.4773+0.699+2

Thank you Anil

ruclips.net/p/PL9nSaEI0m9rfcukoGRb3Ia6l_n68wvpYm NCERT LINE BY LINE EXPLANATION

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Pls look into the mechanism Step 1: Hydroboration 1. Formation of the Alkylborane: Reagents: An alkene and borane (BH₃) or a borane derivative (like BH₃·THF) - **Mechanism:** The boron atom in BH₃ has an empty p orbital and can act as an electrophile. The π electrons of the alkene attack the boron atom, leading to the formation of a four-membered transition state. - **Regioselectivity:** The boron atom adds to the less substituted carbon (anti-Markovnikov addition), and the hydrogen adds to the more substituted carbon. This results from the boron being sterically hindered, preferring the less hindered carbon of the alkene. Step 1: {RCH=CH₂ + BH₃ → RCH₂-CH₂-BH₂} Step 2: Oxidation of the Alkylborane: - **Reagents:** Alkylborane and hydrogen peroxide (H₂O₂) in a basic medium (usually NaOH). - **Mechanism:** The hydroperoxide anion (HO₂⁻) attacks the boron atom, forming a trialkyl borate intermediate. - **Mechanism:** The trialkyl borate intermediate then undergoes hydrolysis to yield the corresponding alcohol and boric acid. {RCH₂-CH₂-BH₂ + H₂O₂/NaOH → RCH₂-CH₂-OH + B(OH)₃} Detailed Mechanism: 1. **Formation of the Alkylborane:** - The π electrons of the alkene attack the boron atom of BH₃. - A four-membered transition state forms, leading to the anti-Markovnikov addition product. 2. **Oxidation to Alcohol:** - The alkylborane reacts with hydrogen peroxide in the presence of a base. - The hydroperoxide anion attacks the boron atom, leading to the formation of a borate ester. - The borate ester is hydrolyzed to produce the alcohol and boric acid. Example Reaction: For 1-butene: 1. Hydroboration: CH₃-CH₂-CH=CH₂ + BH₃ → CH₃-CH₂-CH₂-CH₂-BH₂ 2. Oxidation: CH₃-CH₂-CH₂-CH₂-BH₂ + H₂O₂/NaOH → CH₃-CH₂-CH₂-CH₂-OH + B(OH)₃ In summary, the hydroboration-oxidation reaction is a valuable method for synthesizing alcohols from alkenes with anti-Markovnikov regioselectivity, providing a straightforward pathway to primary alcohols.

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Thank you ma'am

How ar you anandhi?

@@Worldofchemistryclass11and12 I am fine mam

Thank you so much lavmanu.Happy learning

Not to worry WOC is always with you. Pls start watching one shot videos kept in playlists. 2024-25 preparation will be done as per new exam pattern. Believe in yourself kim

@@Worldofchemistryclass11and12 thank you, ma'am(◍•ᴗ•◍)

Happy learning

My husband

@@Worldofchemistryclass11and12 great mam 👍

12 years pyqs are done. Pls check the playlist.Happy learning varshini

@@Worldofchemistryclass11and12 tq mam❤

Can you provide the playlist mam

True..pls share your experience as a video..we will show it to public

@@Worldofchemistryclass11and12 mam I not a victim but I heard this from my senior's, the app which claims we will provide loan after login it and will ask some money to deposit like 2000,3000 after that we will loved out by them and we lost our money , this type of scam going on students especially in Bengaluru ,Chennai.

Happy learning

But not at the cost of human health

@@Worldofchemistryclass11and12 🥲👌

Thank you Yogi.. Wonderful to have you in my channel

She teaches chemistry the same way too... you would never feel you are learning with her.. but every word she speak would get into our head... vani maam❤❤❤❤

Thank you geethika..God bless u my dear

@@Worldofchemistryclass11and12 love you maam😚😚

Welcome smriti. Happy learning. Inform all your friends to join the session

Don't worry work with me regularly and start watching one shot videos..u will get better understanding

@@Worldofchemistryclass11and12 thank you mam I will 🥰

Thank u geethika..How r u

@@Worldofchemistryclass11and12 I am fine maam... Waiting for NEET results...😚😚

U will get it